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Nov 21, 2017 at 21:39 answer added reuns timeline score: 2
Nov 21, 2017 at 20:48 comment added reuns No. We are looking at $\mathcal{D} = \{ \sum_{n=1}^\infty a_n n^{-s} = \prod_{j=1}^l L(s,\chi_j)^{e_j}, e_j \in \mathbb{Z}\}$, no sum here. The question is what is $T \mathcal{D}$ and how to put a ring structure on it. The first step is to write a formula for $\log \prod_{j=1}^l L(s,\chi_j)^{e_j}$ and to define $T$ in term of it.
Nov 21, 2017 at 20:30 comment added Sylvain JULIEN T is a projection : the sum of the images is the image of a sum.
Nov 21, 2017 at 20:22 comment added reuns And $T f(s) \times Tg(s)$ ? And more important how do you know $T f(s) + Tg(s),T f(s) \times Tg(s)$ are in the image of $T$ ?
Nov 21, 2017 at 20:13 comment added Sylvain JULIEN Let us continue this discussion in chat.
Nov 21, 2017 at 20:11 comment added Sylvain JULIEN $ Tf(s)+Tg(s)=\sum_{p}p^{-s}(\sum_{j=1}^{l}e_{j}\chi_{j}(p)+\sum_{k=1}^{m}f_{k}\chi_{k}(p)) $ with $ g(s)=\prod_{k=1}^{m}L(s,\chi_{k})^{f_{k}} $ .
Nov 21, 2017 at 19:55 comment added reuns First step : if $f(s) = \sum_{n=1}^\infty a_n n^{-s} = \prod_{j=1}^l L(s,\chi_j)^{e_j}, e_j \in \mathbb{Z}$ then $Tf(s)=\sum_p a_p p^{-s} = \sum_p p^{-s} \sum_{j=1}^l e_j\chi_j(p)$. How do you define $Tf(s) + Tg(s)$ and $Tf(s) \times Tg(s)$ to make the image of $T$ a ring ?
Nov 21, 2017 at 19:31 comment added reuns of course...${}{}$
Nov 21, 2017 at 19:27 comment added Sylvain JULIEN @reuns: what exactly do you denote by $\mathcal{P}$? The set of prime numbers?
Nov 21, 2017 at 18:12 comment added reuns @SylvainJULIEN When considering only products and quotients of Dirichlet L-functions what I wrote is trivial, can you show it ?
Nov 21, 2017 at 10:47 comment added Sylvain JULIEN @Qiaochu Yuan : I'd be interested in knowing what happens with as many morphisms as possible given this double structure, for different definitions of the tensor product.
Nov 21, 2017 at 5:41 comment added reuns Of functions $\mathcal{P} \to \mathbb{C}$ quotiented by "equal on all but finitely many primes" (so that it doesn't contain non-primitive Dirichlet L functions)
Nov 21, 2017 at 5:32 comment added reuns Under the automorphy and Langlands conjectures, isn't the operator $\sum_{n=1}^\infty a_n n^{-s} \mapsto\sum_p a_p p^{-s}$ injective on the products and quotients of normalized L-functions and its image is a ring with the pointwise addition and multiplication of functions $\mathcal{P} \to \mathbb{C}$
Nov 21, 2017 at 0:23 comment added Qiaochu Yuan Nothing; with only the given hypotheses $C$ could be a discrete category with only identity morphisms, and then $C$ with this extra structure could be any commutative semiring.
Nov 21, 2017 at 0:23 comment added Noah Snyder Why would you expect this? What’s the tensor product? What’s Homs from the Riemann zeta to itself?
Nov 21, 2017 at 0:23 history edited Sylvain JULIEN CC BY-SA 3.0
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Nov 21, 2017 at 0:17 history asked Sylvain JULIEN CC BY-SA 3.0