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Jun 6, 2020 at 4:53 history edited Pedja CC BY-SA 4.0
Fixed broken link
Jun 6, 2020 at 4:46 comment added Simd What was the conclusion on this new test? Did it turn out to be correct/faster/better?
Jun 6, 2020 at 3:17 history edited Pedja CC BY-SA 4.0
Added two more journals
Apr 20, 2020 at 4:53 history edited Pedja CC BY-SA 4.0
Added link to the Google Play
Jan 26, 2020 at 5:11 history edited Pedja CC BY-SA 4.0
Updated a link to the Sage Math Cell
Nov 27, 2019 at 20:08 answer added Max Alekseyev timeline score: 7
Nov 22, 2019 at 10:03 history edited Pedja CC BY-SA 4.0
added link to the Amazon App Store
Nov 7, 2019 at 9:35 comment added Pedja @DavidESpeyer Journal of Number Theory also allows authors to make their individual articles open.
Nov 6, 2019 at 16:26 comment added David E Speyer Not that I think I am going to earn the reward, but could you please choose a non-Elsevier journal? Algebra and Number Theory is an open journal whose standards are at least as high.
Nov 6, 2019 at 16:21 comment added David E Speyer Since no one has said this explicitly yet: It is easy to see that, if $n$ is prime, then $T_n(x) \equiv x^n \bmod n$. Indeed, $T_n(x)$ is the unique polynomial such that $T_n(u+u^{-1}) = u^n + u^{-n}$ and, if $n$ is prime and we take coefficients modulo $n$, then $x^n$ has this property.
Nov 6, 2019 at 11:11 history edited Pedja CC BY-SA 4.0
added link to the gist
Oct 17, 2019 at 14:04 history edited Pedja CC BY-SA 4.0
Offered a bounty
Jul 6, 2019 at 14:58 comment added Pedja Generalization of this claim and an attempted proof of it can be found here.
May 14, 2019 at 20:43 history edited Pedja CC BY-SA 4.0
Added link to the Sage Cell
Dec 7, 2017 at 5:10 comment added Dendi Suhubdy @IgoRivin We tried implementing the algorithm in C++ here without directly computing T_n(x) github.com/dendisuhubdy/Chebyshev-primality-test/blob/master/…. This is really cool!
S Nov 26, 2017 at 13:42 history bounty ended Pedja
S Nov 26, 2017 at 13:42 history notice removed Pedja
Nov 21, 2017 at 18:53 comment added მამუკა ჯიბლაძე @IgorRivin Thanks to the answer by Lucia to that question, I believe the answer to your question is more than positive - seems like this produces a logarithmically efficient primality test. I tried to demonstrate it in another answer below.
Nov 21, 2017 at 18:47 answer added მამუკა ჯიბლაძე timeline score: 33
Nov 21, 2017 at 13:38 comment added მამუკა ჯიბლაძე I've now posted a separate question about that
Nov 21, 2017 at 12:29 comment added მამუკა ჯიბლაძე @IgorRivin Seems that it depends on how fast one can find $T_n(x)\mod x^r-1$ (for very small $r$, about $\log n$) without computing $T_n(x)$ itself completely. The way it is implemented now, the whole $T_n(x)$ is found first, and I think it is worse than polynomial then.
Nov 19, 2017 at 18:32 answer added მამუკა ჯიბლაძე timeline score: 8
Nov 19, 2017 at 15:01 history edited Pedja
retaged
S Nov 19, 2017 at 13:50 history bounty started Pedja
S Nov 19, 2017 at 13:50 history notice added Pedja Draw attention
Nov 19, 2017 at 10:48 history edited Pedja CC BY-SA 3.0
simplified the code
Nov 18, 2017 at 8:01 comment added Pedja @IgorRivin Please see analysis at the top of the page 8 . Since these two algorithms are similar their time complexities should be the same .
Nov 17, 2017 at 17:07 comment added Igor Rivin This is very cool, but, if true, can it be made into a useful algorithm? As stated it is about an $O(n^2)$ algorithm to determine primality of $n$
Nov 17, 2017 at 16:04 comment added Pedja @მამუკა ჯიბლაძე A stack overflow error has occurred .
Nov 17, 2017 at 14:57 comment added მამუკა ჯიბლაძე I tried it with $n=311231$ and got this: PARI/GP interpreter crashed -- automatically restarting. *** at top-level: if(Mod((polchebyshev(n,1,x))%(x^r-1),n)-( *** ^-------------------- *** incorrect type in gtos [integer expected] (t_POL).
Nov 17, 2017 at 13:49 history asked Pedja CC BY-SA 3.0