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Nov 15, 2017 at 16:51 vote accept Dmitrii Korshunov
Nov 15, 2017 at 16:45 comment added Gro-Tsen @DmitryK My example is $2$-dimensional: the Clebsch diagonal cubic surface is defined in the ($3$-dimensional) hyperplane $\sum_{i=0}^4 X_i=0$ inside $\mathbb{P}^4$ for symmetry, but by seeing this hyperplane as $\mathbb{P}^3$, it is a smooth surface in $\mathbb{P}^3$.
Nov 15, 2017 at 16:32 comment added Dmitrii Korshunov Great, thank you! Although I was looking for a hypersurface example, your computation demonstrates non-associativity on 3d Fermat cubic $\sum_{i=0}^4 X_i^3 = 0$ as well. But I'm still not sure about 2-dimensional cubic hypersurface.
Nov 15, 2017 at 15:03 history answered Gro-Tsen CC BY-SA 3.0