Timeline for Pde system problem
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 15, 2017 at 11:53 | vote | accept | MathDG | ||
| Nov 15, 2017 at 10:36 | answer | added | Robert Bryant | timeline score: 12 | |
| Nov 15, 2017 at 10:12 | comment | added | Igor Khavkine | @exxxit8, all these different cases are quite similar. So if you don't understand the $c\ne 0$ case, I'm sorry to say, then you probably don't understand the other cases either. What you should do first is thoroughly understand the cases where the solution is known. | |
| Nov 15, 2017 at 6:44 | comment | added | MathDG | @Igor Khavkine, thank you very much, but I don't understand for $c$ not zero. | |
| Nov 15, 2017 at 6:42 | comment | added | MathDG | @Alexander Pigazzini, thank you very much | |
| Nov 15, 2017 at 6:15 | comment | added | MathDG | @exxxit8, for exemple $h=c=0$ implies $f$ harmonic, and the result is the same for $h \neq 0$ and $c=0$, i.e. $h \neq 0$ and $f=0$, or $h=0$ and $f=$constant. | |
| Nov 15, 2017 at 1:21 | comment | added | Igor Khavkine | @exxxit8, I strongly encourage you to first work through the steps of the $h=c=0$ and $c=0,h\ne 0$ cases, and then apply the same method to the $c\ne 0$ case. | |
| Nov 14, 2017 at 21:46 | history | edited | MathDG | CC BY-SA 3.0 |
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| Nov 14, 2017 at 19:19 | comment | added | Ben McKay | If you have two different questions, why not ask them separately? It will be easier to understand the questions and the answers if you ask the questions separately. | |
| Nov 14, 2017 at 19:18 | vote | accept | MathDG | ||
| Nov 15, 2017 at 11:53 | |||||
| Nov 14, 2017 at 19:13 | answer | added | Igor Khavkine | timeline score: 3 | |
| Nov 14, 2017 at 18:42 | comment | added | MathDG | @Willie Wong, No, are two separate case.. I said that badly, sorry! | |
| Nov 14, 2017 at 18:23 | comment | added | Willie Wong | I don't understand your question, you have a system of two PDEs about a scalar function $f$ (which means surely your system is overdetermined). But then you say that simultaneously $f$ is defined on $\mathbb{R}^2$ and a surface $S$: which is it? | |
| Nov 14, 2017 at 16:46 | comment | added | MathDG | @Chris Ramsey, I found a particular manifold with Einstein condition in isotropic space... $f$ is defined on surface and it is a positive scalar function | |
| Nov 14, 2017 at 16:42 | history | edited | MathDG | CC BY-SA 3.0 |
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| Nov 14, 2017 at 16:39 | comment | added | Chris Ramsey | Please give some context as to why you are interested in this problem. | |
| Nov 14, 2017 at 16:08 | review | First posts | |||
| Nov 14, 2017 at 16:39 | |||||
| Nov 14, 2017 at 16:05 | history | asked | MathDG | CC BY-SA 3.0 |