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Nov 13, 2017 at 4:20 comment added usul This question is confusing because you mention P=NP in your last sentence, but the previous one sounds like you do not understand the P vs NP problem and the how the TSP relates to it...
Nov 12, 2017 at 23:25 comment added Sasho Nikolov @DendiSuhubdy What does this fact about random TSP instances have to do with the computational complexity of the problem?
Nov 12, 2017 at 18:19 answer added Timothy Chow timeline score: 11
Nov 12, 2017 at 15:42 comment added Dendi Suhubdy See the Beardwood–Halton–Hammersley Theorem theoremoftheday.org/OR/BHH/TotDBHH.pdf
Nov 12, 2017 at 15:12 answer added user117147 timeline score: 8
Nov 12, 2017 at 14:45 comment added Emil Jeřábek The existence of such a thing is equivalent to P = NP. Hence we can’t.
Nov 12, 2017 at 14:26 history asked Simon Rose CC BY-SA 3.0