Skip to main content
6 events
when toggle format what by license comment
Nov 10, 2017 at 21:44 vote accept Edouard
Nov 10, 2017 at 16:46 answer added Dylan Wilson timeline score: 2
Nov 10, 2017 at 15:05 history edited Edouard CC BY-SA 3.0
added 168 characters in body
Nov 10, 2017 at 15:03 comment added Edouard Yes, will edit.
Nov 10, 2017 at 14:22 comment added Tim Campion An $(n,k)$ category $\mathcal{M}$ is in particular an $(n,1)$-category by discarding noninvertible higher morphisms. Latching and matching are certain (co)limits, and thus depend only on the $(n,1)$-structure of $\mathcal{M}$. So it suffices to show this when $\mathcal{M}$ is an $(\infty,1)$-category. Then if $\mathcal{M}$ is presented as a model category, this is just the usual theory of the Reedy model structure. Are you particularly interested in cases where $\mathcal{M}$ is not presented as a model category?
Nov 10, 2017 at 13:51 history asked Edouard CC BY-SA 3.0