Timeline for Trace of non-commutable matrices
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 8, 2017 at 13:27 | comment | added | Igor Rivin | @Koltchinskii I was assuming both of them were symmetric... | |
| Nov 8, 2017 at 8:38 | comment | added | Dan Fox | Another proof is $0 \leq \text{tr}[A, B]^{t}[A, B] = 2\text{tr}(A^{2}B^{2}) - 2\text{tr}(ABAB)$, for symmetric $A$ and $B$. | |
| Nov 8, 2017 at 6:18 | comment | added | Nikolayevich | So it seems we only need to assume one of them is symmetric. | |
| Nov 8, 2017 at 6:15 | vote | accept | Nikolayevich | ||
| Nov 8, 2017 at 6:15 | |||||
| Nov 8, 2017 at 3:09 | history | answered | Igor Rivin | CC BY-SA 3.0 |