Skip to main content
8 events
when toggle format what by license comment
Nov 8, 2017 at 4:29 comment added Zitao Wang Thanks for the reference, Ryan. The combinatorial representation in v2 of the paper looks somewhat obscure to me. For the spin case, it should be equivalent to the Kasteleyn orientation I mentioned above, though not in a way that's clear to me. It would be great if this connection is point out explicitly in the new version and that the combinatorial representation for spin$^{\mathbf{C}}$ can also be written in a way similar to the Kasteleyn orientation.
Nov 8, 2017 at 3:45 comment added Ryan Budney The revised version (v3) should appear on the arXiv tomorrow. Hopefully it's far less painful to read.
Nov 8, 2017 at 3:35 comment added Ryan Budney Yes, there are similar combinatorial representations. The 2nd link you give cites my preprint. The last section of my preprint shows how you adapt the first part of the paper to describe $Spin^c$ structures in the same language. I'll update my preprint soon as I think (sigh!) the version on the arXiv is still difficult to read in spots.
Nov 8, 2017 at 2:00 comment added HYL In general $\text{spin}^{\mathbf{C}}$-structures correspond to homotopy classes of complex structures over the 2-skeleton which can be extended to the 3-skeleton. So for surfaces, $\text{spin}^{\mathbf{C}}$-structures correspond to homotopy classes of complex structures on the triangulation.
Nov 7, 2017 at 20:00 comment added Zitao Wang 2D means two dimension. Yes, the spin$^{\mathbf{C}}$ structures are integral lifts of $w_2$. But I'm not sure how to translate this into the orientations of the edges of the graph on the manifold. i.e., something analogous to the Kasteleyn orientation.
Nov 7, 2017 at 19:51 history edited Zitao Wang CC BY-SA 3.0
added 24 characters in body
Nov 7, 2017 at 19:26 comment added Alex Degtyarev Is $2D$ two or even? As far as I remember, $\operatorname{Spin}^{\mathbb{C}}$-structures are the integral lifts of $w_2$. If $2D=2$ and, hence, $w_2=0$, there is a distinguished lift, do the set is naturally isomorphic to $\mathbb{Z}$.
Nov 7, 2017 at 19:12 history asked Zitao Wang CC BY-SA 3.0