Skip to main content
9 events
when toggle format what by license comment
Nov 9, 2017 at 5:58 vote accept Turbo
Nov 4, 2017 at 22:34 history edited Turbo CC BY-SA 3.0
deleted 62 characters in body
Nov 4, 2017 at 22:24 comment added Turbo @JohannesHahn 1. I would not know how to compute binomial coefficients mod $q$ in poly time. 2. I do not know why this is useful at all.
Nov 4, 2017 at 22:21 history edited Turbo CC BY-SA 3.0
added 53 characters in body
Nov 4, 2017 at 22:21 comment added Johannes Hahn @Turbo The very first step of the euclidean algorithm is replacing c with c modulo q. So you can just compute the binomial coefficient modulo q in the first place to avoid that particular problem.
Nov 4, 2017 at 22:17 answer added Jan-Christoph Schlage-Puchta timeline score: 5
Nov 4, 2017 at 21:56 comment added Turbo $c=\binom{b}{a-1}$ could be large (say $a=5\times 10^{100}, b=6\times 10^{100}$ (also I do not get why use $gcd(q,c)$))?
Nov 4, 2017 at 21:53 comment added Gerhard Paseman If a+2 is less than b+2 is less than a+a, start with gcd(q,c) where c = b choose a-1. Otherwise split the interval up. Gerhard "Best Way Known To Me" Paseman, 2017.11.04.
Nov 4, 2017 at 21:11 history asked Turbo CC BY-SA 3.0