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As Will Sawin points out, the following is mostly an answer to the question "Is it true that the set of primes such that $\rho_p$ is reducible is finite?" which is related but strictly stronger than the question actually asked.

That question admits a negative answer, but a positive answer if $E$ has no complex multiplication. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible. As Will Sawin points out, even in that case, the representation $\rho_p$ is nevertheless irreducible for infinitely many $p$. Indeed, for $p$ inert in $K$, $\rho_p$ is a representation in the unit group of a free module of rank 1 over the localization at $p$ of the order $\operatorname{End}_F(E)$ and the fact that such a representation is surjective for almost all such $p$ follows.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

As Will Sawin points out, the following is an answer to the question "Is it true that the set of primes such that $\rho_p$ is reducible is finite?" which is related but strictly stronger than the question actually asked.

That question admits a negative answer, but a positive answer if $E$ has no complex multiplication. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

As Will Sawin points out, the following is mostly an answer to the question "Is it true that the set of primes such that $\rho_p$ is reducible is finite?" which is related but strictly stronger than the question actually asked.

That question admits a negative answer, but a positive answer if $E$ has no complex multiplication. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible. As Will Sawin points out, even in that case, the representation $\rho_p$ is nevertheless irreducible for infinitely many $p$. Indeed, for $p$ inert in $K$, $\rho_p$ is a representation in the unit group of a free module of rank 1 over the localization at $p$ of the order $\operatorname{End}_F(E)$ and the fact that such a representation is surjective for almost all such $p$ follows.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

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ThisAs Will Sawin points out, the following is indeed well-knownan answer to be notthe question "Is it true that the set of primes such that $\rho_p$ is reducible is finite?" which is related but strictly stronger than the question actually asked.

That question admits a negative answer, but almost truea positive answer if $E$ has no complex multiplication. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

This is indeed well-known to be not true, but almost true. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

As Will Sawin points out, the following is an answer to the question "Is it true that the set of primes such that $\rho_p$ is reducible is finite?" which is related but strictly stronger than the question actually asked.

That question admits a negative answer, but a positive answer if $E$ has no complex multiplication. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

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This is indeed well-known to be not true, but almost true. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is actually muchsignificantly easier andas it follows quite easilyrapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the articlearticles of Agnès David and Nicolas Billerey are recommended.

This is indeed well-known to be not true, but almost true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible is actually much easier and follows quite easily from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves.

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the article of Agnès David and Nicolas Billerey are recommended.

This is indeed well-known to be not true, but almost true. If $E$ has no complex multiplication (that is to say if $\operatorname{End}_F(E)=\mathbb Z$), a good deal more is actually true.

Theorem (Serre, 1972): Assume $E/F$ is without complex multiplication. Then the Galois representation $\rho_p:\operatorname{Gal}(\bar{F}/F)\longrightarrow\operatorname{Aut}(E[p])$ is surjective for all $p$ except a finite number.

The fact that all $p$ except possibly a finite number are such that $\rho_p$ is irreducible, not to mention the fact that there are infinitely many $p$ such that $\rho_p$ is irreducible, is significantly easier as it follows quite rapidly from the theorem of Shafarevich on the finiteness of the set of isomorphism classes of $F$-isogenous elliptic curves (see Abelian $\ell$-adic Representations and Elliptic Curves Jean-Pierre Serre, 1968).

However, if $E$ has complex multiplication by a quadratic imaginary subfield $K$ of $F$, consider $p$ a prime splitting as $\pi\bar{\pi}$ in $K$. Then $E[\pi]$ is a set of $F$-rational points of order $p$. In that case, there is a thus an infinite number of prime such that $\rho_p$ is reducible.

On that topic, the articles of Agnès David and Nicolas Billerey are recommended.

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