Timeline for Equivariant Kodaira embedding
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
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| Nov 2, 2017 at 9:29 | comment | added | Piotr Achinger | Yes. Some power $L^n$ is very ample and equivariant, so the group acts on the space of sections $V=H^0(X, L^n)$. Them the embedding $X\to \mathbb{P}(V)$ (or $X\to \mathbb{P}(V^\vee)$, depending on your convention) is equivariant. | |
| Nov 2, 2017 at 5:04 | history | asked | Vamsi | CC BY-SA 3.0 |