Skip to main content
18 events
when toggle format what by license comment
Nov 2, 2017 at 15:09 vote accept Turbo
Nov 2, 2017 at 15:09 vote accept Turbo
Nov 2, 2017 at 15:09
Nov 2, 2017 at 15:09 vote accept Turbo
Nov 2, 2017 at 15:09
Nov 2, 2017 at 15:01 comment added Wlodek Kuperberg Let us continue this discussion in chat.
Nov 2, 2017 at 15:00 comment added Turbo I meant $\sqrt2-\epsilon$ at any $\epsilon\in(0,\sqrt2-1)$.
Nov 2, 2017 at 14:59 comment added Wlodek Kuperberg @Turbo: From your comments I gather that you allow lattice points on the boundary of $K$, even though you said $|K\cap \mathbb{Z}^n|=0$.
Nov 2, 2017 at 14:57 vote accept Turbo
Nov 2, 2017 at 14:59
Nov 2, 2017 at 14:52 comment added Wlodek Kuperberg Right. The way the example is constructed, the John's e ellipsoid is a sphere. Of course, the product could use a line segment longer than $d$, in which case some of the axes of the ellipsoid could be arbitrarily long.
Nov 2, 2017 at 14:46 comment added Turbo yes... but my main argument was about smallest axis smaller than $1$ necessary which is disproved in your case with smallest axis $\sqrt 2$ or $\sqrt k$ in general.
Nov 2, 2017 at 14:43 history edited Wlodek Kuperberg CC BY-SA 3.0
added 2 characters in body
Nov 2, 2017 at 14:42 comment added Wlodek Kuperberg @Turbo: Thanks for the correction. I changed "radius" to "diameter", which is what I meant.
Nov 2, 2017 at 14:39 comment added Turbo $K_2\times [0,d]^{n-2}$ contains John's ellipsoid with smallest axis $\sqrt2$ (not sphere of radius $d$).
Nov 2, 2017 at 14:36 history edited Wlodek Kuperberg CC BY-SA 3.0
edited body
Nov 2, 2017 at 12:50 history edited Wlodek Kuperberg CC BY-SA 3.0
extended construction
Nov 2, 2017 at 12:46 history undeleted Wlodek Kuperberg
Nov 2, 2017 at 2:19 history deleted Wlodek Kuperberg via Vote
Nov 2, 2017 at 2:17 history edited Wlodek Kuperberg CC BY-SA 3.0
specific example described
Nov 2, 2017 at 2:10 history answered Wlodek Kuperberg CC BY-SA 3.0