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Nov 3, 2017 at 0:13 comment added tarik also it is possible to using $nil ker\mu_A$ where $A$ is a CDGA of the rational homotopy type of the space $X$ with multiplication $\mu_A$, because $TC(X_\Bbb{Q})\leq~nil ker\mu_A$
Nov 2, 2017 at 19:02 answer added Mark Grant timeline score: 2
Nov 2, 2017 at 8:03 answer added Jeff Strom timeline score: 3
Nov 1, 2017 at 23:42 comment added tarik I very much doubt that the dimension of cohomology is greater
Nov 1, 2017 at 22:42 history edited YCor
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Nov 1, 2017 at 22:09 history asked tarik CC BY-SA 3.0