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David E Speyer
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It is not always a monomorphism. Let X be R^2 \setminus { (x,y) : x^2 + y^2 <=< 1 }. Then X has fundamental group the integers, but Y is contractible.

It is not always a monomorphism. Let X be R^2 \setminus { (x,y) : x^2 + y^2 <= 1 }. Then X has fundamental group the integers, but Y is contractible.

It is not always a monomorphism. Let X be R^2 \setminus { (x,y) : x^2 + y^2 < 1 }. Then X has fundamental group the integers, but Y is contractible.

Source Link
David E Speyer
  • 156.4k
  • 14
  • 422
  • 763

It is not always a monomorphism. Let X be R^2 \setminus { (x,y) : x^2 + y^2 <= 1 }. Then X has fundamental group the integers, but Y is contractible.