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Oct 25, 2017 at 7:28 comment added მამუკა ჯიბლაძე What exactly do you mean by a down-set of $B$? At least three readings come to mind: (1) a subset $D$ of $B$ with $b\in B\ \&\ d\in D\ \&\ b<d$ implying $b\in D$; (2) a subset $D$ of $\omega$ with $d\in D$ implying existence of $b\in B$ with $d\leqslant b$; or (3) same as (2) and in addition $n\in\omega\ \&\ n<d\ \&\ d\in D$ implying $n\in D$.
Oct 25, 2017 at 6:05 vote accept Dominic van der Zypen
Oct 25, 2017 at 6:00 vote accept Dominic van der Zypen
Oct 25, 2017 at 6:04
Oct 25, 2017 at 5:50 answer added Bjørn Kjos-Hanssen timeline score: 3
Oct 25, 2017 at 5:22 history asked Dominic van der Zypen CC BY-SA 3.0