Timeline for Two embedded symplectic spheres with zero square in a symplectic $4$-manifold
Current License: CC BY-SA 3.0
11 events
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Oct 22, 2017 at 16:55 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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Oct 22, 2017 at 14:27 | comment | added | Marco Golla | I can't find the reference you are giving in McDuff and Salamon. In any case, if you blow-up $\Sigma\times S^2$, then you still have plenty of 0-spheres, but the 4-manifold is not a fibre bundle (not even topologically). (Relative) minimality is a key assumption in McDuff's theorem. | |
Oct 22, 2017 at 13:58 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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Oct 22, 2017 at 13:35 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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Oct 22, 2017 at 13:02 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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Oct 22, 2017 at 12:55 | comment | added | Tsemo Aristide | Minimality is not mentioned in the reference above. | |
Oct 22, 2017 at 12:24 | history | undeleted | Tsemo Aristide | ||
Oct 22, 2017 at 12:24 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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Oct 22, 2017 at 12:20 | history | deleted | Tsemo Aristide | via Vote | |
Oct 22, 2017 at 12:11 | comment | added | Marco Golla | The existence of the diffeomorphism $e_i$ requires that $M$ be minimal (which is not assumed, here). Moreover, it's not true that $H_2$ of an irrational ruled surface has one generator; e.g. $H_2(\Sigma\times S^2) = \mathbb{Z}^2$, generated by a section and a fibre. (This is true for all bundles, actually.) | |
Oct 22, 2017 at 12:05 | history | answered | Tsemo Aristide | CC BY-SA 3.0 |