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Oct 27, 2017 at 6:03 comment added Tim Porter Dan: your first sentence is highly contentious. Many 'spaces' arising in geometry (in algebraic geometry at least) are not of that form. I feel that the 'combinatorial' nature of many spaces, then, almost suggests that the spatial structure is not really what is being studied by the homotopy type invariants. I used to say that when a topologist say 'given a space, $X$' one should ask 'how is it given?'. If an analyst asks for invariants of a space occurring in their work, it may not be a CW-complex, but using Cech-type methods one can use CW-complex methods in its study.
Oct 23, 2017 at 21:56 comment added Dan Ramras I think that since most of the "geometric" and "combinatorial" spaces that occur in mathematics - that is, manifolds, real and complex algebraic varieties, spaces built from combinatorial data like categories and posets - have the homotopy type of CW complexes, one can break the circularity so to speak by beginning with such objects as the motivating examples. Then they happen to fit into a nice class of objects - spaces of the homotopy type of a CW complex - for which higher homotopy groups are a very useful invariant.
Oct 23, 2017 at 13:25 comment added Steve Costenoble Absolutely, regarding the complication. I didn't mention that, but stated the result carefully with it in mind.
Oct 23, 2017 at 6:06 comment added Tim Porter There is one added complication, Steve, and that given two spaces that you know the homotopy groups of, and yeah they are isomorphic, you still have to construct a suitable map realising the isomorphisms. This realisation problem was there from the start in J. H. C. Whitehead's fundamental Combinatorial Homotopy papers (late 1949s, early 1950s) and have been explored a lot by Baues in his books. The circularity that you point out is one reason why CW-complexes are where the rapid expansion of algebraic topology concentrated at least initially.
Oct 22, 2017 at 15:54 comment added მამუკა ჯიბლაძე @TylerLawson if I am not mistaken, homotopy groups of finite topological spaces are isomorphic to the homotopy groups of the geometric realizations of the corresponding preorders.
Oct 21, 2017 at 23:45 history made wiki Post Made Community Wiki by Todd Trimble
Oct 21, 2017 at 20:00 comment added Tyler Lawson I agree, and this is probably going to be a problem for somebody who (as the questioner said) has a background in arithmetic geometry and often encounters topological spaces of a very different type.
Oct 21, 2017 at 19:25 history answered Steve Costenoble CC BY-SA 3.0