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Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

 

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function, which is well-known function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.

Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

 

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function, which is well-known function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.

Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function, which is well-known function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.

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user111966
user111966

Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function, which is well-known function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.

Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.

Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function, which is well-known function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.

Source Link
user111966
user111966

Perhaps this is a duplicate of this question If the Riemann Hypothesis fails, must it fail infinitely often?.

The discussion continues here The Hardy Z-function and failure of the Riemann hypothesis, where a hypothesis is proposed, which implies If the Riemann Hypothesis fails, must it fail infinitely often?.

To this hypothesis there are two approximations based on: 1. Zeta function universality 2. GUE hypothesis.

Concerning 1. I can say that even, $\zeta (s)$ for $Re(s)=\frac{1}{2}$ is dense in $\mathbb{C}$, is unknown.

2. it seems to me it will be easier. It is enough to make an inversion for the expression $N(t_{n})=n$, where $N(t_{n})$ the number of non-trivial zeros of the zeta function and $t_{n}$ the nth non-trivial zero, and define the property of the recurrence.