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Jun 17, 2010 at 9:58 vote accept Anirbit
S Jun 17, 2010 at 9:58 vote accept Anirbit
Jun 17, 2010 at 9:58
Jun 17, 2010 at 9:58 vote accept Anirbit
S Jun 17, 2010 at 9:58
Jun 16, 2010 at 15:45 answer added Diego Matessi timeline score: 1
Jun 16, 2010 at 15:12 answer added Deane Yang timeline score: 4
Jun 16, 2010 at 15:07 answer added Vít Tuček timeline score: 2
Jun 16, 2010 at 15:06 comment added Diego Matessi ...in my previous comment $p=1$ in the first case and $p=2$ in the second....
Jun 16, 2010 at 15:03 comment added Diego Matessi $dfX$ means $df \otimes X$ which is a section of $\wedge^p T^*M \otimes E$. Similarily $d\omega X$ means $d\omega \otimes X$.
Jun 16, 2010 at 14:53 history asked Anirbit CC BY-SA 2.5