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Aug 1, 2010 at 11:26 vote accept Graviton
Jun 29, 2010 at 11:25 comment added Joseph O'Rourke @TonyK: Thanks for the correction, now edited. In practice I have simply averaged the two x-coordinates, although your method may be more accurate.
Jun 29, 2010 at 11:24 history edited Joseph O'Rourke CC BY-SA 2.5
parallel->perpendicular, thanks to TonyK
Jun 17, 2010 at 18:41 comment added TonyK I think you meant 'perpendicular', not 'parallel'. Another wrinkle is that this method generates two values for the x-coordinate of the centroid, and you have to decide what to do when they are not equal due to rounding errors. Probably you should take the one that came from the 'least perpendicular' projection, i.e. the one with the greater area A.
Jun 16, 2010 at 13:02 comment added JBL Well, I would have voted you up in any case. :) Mentioning the "extra wrinkle" is good, too.
Jun 16, 2010 at 12:49 history answered Joseph O'Rourke CC BY-SA 2.5