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Nov 3, 2017 at 17:52 comment added VSJ Hi Bill, I'm not sure that is a mistake. Because even then, the eigenvalues will converge to 0 and not 1. Perhaps it is the case that the matrix is tending "pointwise" to identity, but it is not tending fast enough, and therefore the eigenvalues don't converge?
Nov 3, 2017 at 13:33 history edited Bill Bradley CC BY-SA 3.0
Fixed mistake: rescaling down variance by $1/n$.
Nov 3, 2017 at 13:31 comment added Bill Bradley Ah, @VSJ , that is my mistake: I forgot to pass through the prefactor of $1/\sqrt(n)$ in the original definition of $M$. I will fix that now, at which point I think Marcel's answer is consistent with mine.
Nov 2, 2017 at 4:04 comment added VSJ I'm confused about one part: Marcel's answer indicates that $MM^*$ is close to identity. Thus it should have eigenvalues close to 1? But your argument says eigenvalues are iid from a chi square distribution so they aren't all close to 1. How to reconcile these?
Oct 16, 2017 at 12:42 history answered Bill Bradley CC BY-SA 3.0