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Apr 12, 2018 at 9:42 vote accept geodude
Oct 13, 2017 at 21:46 comment added user95282 The following is essentially as in Taras Banakh's answer, but with references to Bogachev: By Prop. 7.2.9 every $\tau$-additive measure has support. As noted in the proof of 7.2.10, the support is separable. By Theorem 7.4.3, every $\tau$-additive measure on a complete separable metric space is tight.
Oct 13, 2017 at 14:21 answer added Taras Banakh timeline score: 6
Oct 13, 2017 at 12:29 history edited geodude CC BY-SA 3.0
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Oct 13, 2017 at 11:46 history edited geodude CC BY-SA 3.0
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Oct 13, 2017 at 9:51 history asked geodude CC BY-SA 3.0