Timeline for Let $u_n\in\mathcal{D}'(\mathbb{R}^n)$ have $u_n\to0$ where $u_n\in C_c^\infty$ have uniformly compact support. Does $u_n\to0$ in $C_c^\infty$? [closed]
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Oct 12, 2017 at 23:46 | history | closed |
Denis Serre Michael Renardy Sebastian Goette Christian Remling Henry.L |
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Oct 12, 2017 at 14:55 | answer | added | Ayman Moussa | timeline score: 1 | |
Oct 12, 2017 at 13:09 | comment | added | Abdelmalek Abdesselam | Try to use the Horvath seminorms as in mathoverflow.net/questions/234025/… | |
Oct 12, 2017 at 10:05 | review | Close votes | |||
Oct 12, 2017 at 23:46 | |||||
Oct 12, 2017 at 7:45 | answer | added | Mateusz Kwaśnicki | timeline score: 1 | |
Oct 12, 2017 at 5:28 | answer | added | saone | timeline score: 3 | |
Oct 12, 2017 at 2:20 | comment | added | Nate Eldredge | At the level of abstract nonsense, I think there ought to be an argument from the closed graph theorem (the spaces $C^\infty_c(B)$ are Frechet). But in such cases there is often a simple direct argument also. | |
Oct 12, 2017 at 2:04 | comment | added | Dominic Wynter | I see. Then how can we deduce that $$\phi\mapsto u*\phi$$ is continuous? | |
Oct 12, 2017 at 2:03 | comment | added | John Pardon | Definitely not: $\varphi(x)\sin(Nx)\to 0$ in $\mathcal D'(\mathbb R)$ as $N\to\infty$ for any compactly supported smooth function $\varphi$. | |
Oct 12, 2017 at 1:47 | history | edited | Dominic Wynter | CC BY-SA 3.0 |
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Oct 12, 2017 at 1:37 | history | asked | Dominic Wynter | CC BY-SA 3.0 |