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Oct 11, 2017 at 15:15 comment added Roger Thank you very much! I just tried on my own following your indications and it seems to be correct. The key of your proof is on your change of variables from $r$ and $l$ to $x$ and $y$. I had calculated the first and second derivative of $f$ before, but with your change of variables you realized that there is no need to consider arbitrary $x$ and $y$, but it is enough to focus on the case where $x<y$ (which as you say is given by the restrictions). That was very smart!
Oct 11, 2017 at 15:08 vote accept Roger
Oct 11, 2017 at 11:56 history bounty ended kakia
Oct 11, 2017 at 1:59 review First posts
Oct 11, 2017 at 2:34
Oct 11, 2017 at 1:56 history answered Chris Grant CC BY-SA 3.0