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Oct 10, 2017 at 0:26 history edited user6976 CC BY-SA 3.0
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Oct 9, 2017 at 23:07 history edited user6976 CC BY-SA 3.0
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Oct 9, 2017 at 21:10 comment added user6976 @EmilJeřábek: OK. You are right. $A^T A$ does not help. The other method (first reduce A to reduced column-echelon form, then look at submatrices of rank $n$) is also more complicated than I thought: too many matrices to consider. So I left only the case $k=n$.
Oct 9, 2017 at 21:06 history edited user6976 CC BY-SA 3.0
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Oct 9, 2017 at 20:48 comment added Emil Jeřábek What about e.g. $A=\binom23$?
Oct 9, 2017 at 20:47 history edited user6976 CC BY-SA 3.0
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Oct 9, 2017 at 17:15 comment added Derek Holt But that only works for square matrices.
Oct 9, 2017 at 17:02 history answered user6976 CC BY-SA 3.0