Timeline for A possible sub-Riemannian structure associated to a non-symmetric matrix
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Oct 10, 2017 at 7:09 | vote | accept | Ali Taghavi | ||
| Oct 9, 2017 at 6:41 | history | edited | Ali Taghavi |
I add a tag "foliation"
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| Oct 8, 2017 at 11:48 | answer | added | Robert Bryant | timeline score: 4 | |
| Oct 8, 2017 at 10:25 | comment | added | Ali Taghavi | @RobertBryant In the case of Lie bracket generating, is the answer obvious?Is the primary decomposition of linear algebra usefull here?(To give a decomposition of the bundle $\ker \alpha $ and a possible obstruction to complete non integrability?) Thanks for your attention to my question. | |
| Oct 7, 2017 at 18:11 | comment | added | Ali Taghavi | @RobertBryant Sorry for my delay in response. Yes I mean the Lie algebra generated by vector fields tangent to $\ker \alpha$ would be the whole space of vector fields.(According to definition of Sub Riemannian manifolds) | |
| Oct 7, 2017 at 13:49 | comment | added | Robert Bryant | The answer depends on what you mean by 'completely non-integrable'. Do you just mean that the kernel of the 1-form $\alpha$ is not Frobenius or do you mean that the kernel of the 1-form is bracket-generating (or something in between)? | |
| Oct 7, 2017 at 9:12 | history | edited | Peter Heinig | CC BY-SA 3.0 |
Purely grammatical improvements. "non integrable" is one of the situations in which a hyphen is required by usual grammatical rules. Meaning and style preserved.
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| Oct 7, 2017 at 8:59 | history | edited | Ali Taghavi | CC BY-SA 3.0 |
added 48 characters in body
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| Oct 7, 2017 at 8:09 | history | edited | Ali Taghavi | CC BY-SA 3.0 |
added 17 characters in body
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| Oct 7, 2017 at 7:55 | history | asked | Ali Taghavi | CC BY-SA 3.0 |