Timeline for Does every convex polyhedron have a combinatorially isomorphic counterpart whose faces all have rational areas?
Current License: CC BY-SA 3.0
11 events
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| Oct 6, 2017 at 16:22 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 6, 2017 at 12:15 | comment | added | Mohammad Ghomi | OK, thanks. I added this condition. | |
| Oct 6, 2017 at 12:14 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 6, 2017 at 11:35 | comment | added | Misha | This argument works for simple polyhedra but not in general: Convex polyhedra close to each other need not be isomorphic. | |
| Oct 6, 2017 at 0:05 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 5, 2017 at 23:56 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 5, 2017 at 22:57 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 5, 2017 at 22:39 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 5, 2017 at 22:08 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 5, 2017 at 21:58 | history | edited | Mohammad Ghomi | CC BY-SA 3.0 |
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| Oct 5, 2017 at 21:32 | history | answered | Mohammad Ghomi | CC BY-SA 3.0 |