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Oct 5, 2017 at 3:38 comment added Vesselin Dimitrov I believe boundedness should be expected in characteristic zero, but proving it might be difficult. There is a simpler problem in linear tori: If $X, Y \subset \mathbb{G}_{m/\mathbb{C}}^3$ are fixed curves, prove that there is an upper bound on the number of points that belong to both $X$ and $[n]Y+Q$, as $n \in \mathbb{Z}$ and $Q \in \mathbb{G}_m^3(\mathbb{C})$ vary in such a way that these curves have no component in common. The original problem may be reduced to this kind of statement inside an abelian variety, replacing $[n]$ by the isogenies of $A$.
Oct 5, 2017 at 3:19 comment added Will Sawin If the Manin-Mumford conjecture were false, a similar technique would work in characteristic zero, using multiplication by $1+n!$. So any technique to prove boundedness would have to be strong enough to prove Manin-Mumford. Don't existing proofs of Manin-Mumford use heavily the Galois action on the torsion points, which seems not usefully available here?
Oct 5, 2017 at 2:23 history edited Felipe Voloch CC BY-SA 3.0
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Oct 4, 2017 at 20:08 history asked Felipe Voloch CC BY-SA 3.0