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Oct 9, 2017 at 13:08 vote accept Sebastien Palcoux
Oct 5, 2017 at 11:43 comment added Henry Cohn That sequence probably isn’t always decreasing (for example, from 23 to 24 it seems not to be). As for $\sqrt{5}$, I haven’t looked at the numbers carefully, but it sounds plausible. Kabatiansky-Levenshtein will certainly prove this for high enough dimensions, and I believe other upper bounds will cover all the remaining cases before that bound kicks in (but I haven’t looked at this carefully, so I’m not as confident as for $\sqrt{6}$).
Oct 5, 2017 at 11:19 comment added Sebastien Palcoux Can we expect $(\tau_n^{1/n})_{n \ge 2}$ to be decreasing ?
Oct 5, 2017 at 11:09 comment added Sebastien Palcoux Do you think that $\sqrt{5}$ is provable as well in dimension $ \ge 4$ ?
Oct 4, 2017 at 18:39 history answered Henry Cohn CC BY-SA 3.0