Timeline for Can a finite group action by homeomorphisms of a three-manifold be approximated by a smooth action?
Current License: CC BY-SA 3.0
5 events
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| Oct 3, 2017 at 15:16 | comment | added | John Pardon | @IgorRivin: in fact Bing himself showed in the very same paper that his exotic involution is a $C^0$-limit of smooth involutions (see my edit to the question for a summary of his construction). | |
| Sep 30, 2017 at 22:47 | comment | added | Igor Rivin | @AndyPutman Yes, I thought that it was something like this, but, as you say, it is not obvious either way. | |
| Sep 30, 2017 at 0:39 | comment | added | Andy Putman | A $C^0$-limit of conjugates of orthogonal maps need not be conjugate to an orthogonal map. It's tempting to think that by passing to subsequences you can ensure that the corresponding sequence of orthogonal maps converge and that the conjugating elements converge (this was also my first impulse when I read the problem), but if you try to write this out carefully it doesn't work. | |
| Sep 30, 2017 at 0:13 | comment | added | John Pardon | I don't insist $\gamma$ and $\tilde\gamma$ be topologically conjugate, just $C^0$ close. | |
| Sep 30, 2017 at 0:02 | history | answered | Igor Rivin | CC BY-SA 3.0 |