Timeline for The $n$-th derivative has $n$ zeros. Can such a function be unbounded?
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Sep 29, 2017 at 0:46 | vote | accept | M. Winter | ||
Sep 28, 2017 at 16:19 | comment | added | Ori Gurel-Gurevich | Right, oops.... | |
Sep 28, 2017 at 16:17 | comment | added | M. Winter | @OriGurel-Gurevich The second derivative has no zeros. See the comments under the Math.SE post. | |
Sep 28, 2017 at 16:16 | comment | added | Ori Gurel-Gurevich | What about $e^{x^2}$? | |
Sep 28, 2017 at 15:46 | answer | added | js21 | timeline score: 17 | |
Sep 28, 2017 at 14:50 | answer | added | Mateusz Kwaśnicki | timeline score: 9 | |
Sep 28, 2017 at 14:17 | history | edited | M. Winter | CC BY-SA 3.0 |
added 12 characters in body
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Sep 28, 2017 at 14:08 | history | asked | M. Winter | CC BY-SA 3.0 |