Timeline for A corollary of Gibbs' inequality
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Oct 2, 2017 at 14:03 | history | edited | Aidan Rocke | CC BY-SA 3.0 |
improved question wording
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| Sep 28, 2017 at 12:43 | vote | accept | Aidan Rocke | ||
| Sep 28, 2017 at 12:40 | answer | added | Dirk | timeline score: 5 | |
| Sep 28, 2017 at 12:39 | answer | added | Fedor Petrov | timeline score: 2 | |
| Sep 28, 2017 at 12:27 | comment | added | js21 | If, say, $p_1^{p_1} > p_2^{p_2}$ then taking $q_1 = p_1 + \varepsilon$ and $q_2 = p_2 - \varepsilon$ (and $q_i = p_i$ for $i>2$) yields a counter-example to this inequality for $\varepsilon$ small enough... | |
| Sep 28, 2017 at 12:22 | history | edited | Aidan Rocke | CC BY-SA 3.0 |
added code
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| Sep 28, 2017 at 12:08 | comment | added | Aidan Rocke | @CarloBeenakker Thank you for the clarification. | |
| Sep 28, 2017 at 12:07 | history | edited | Aidan Rocke | CC BY-SA 3.0 |
fixed question
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| Sep 28, 2017 at 11:49 | comment | added | Carlo Beenakker | your $\geq$ should be $\leq$. | |
| Sep 28, 2017 at 11:27 | history | edited | Aidan Rocke | CC BY-SA 3.0 |
improved question details
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| Sep 28, 2017 at 11:18 | history | edited | Aidan Rocke | CC BY-SA 3.0 |
simplified question
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| Sep 28, 2017 at 11:13 | history | asked | Aidan Rocke | CC BY-SA 3.0 |