Timeline for Maximum area of the intersection of a parallelogram and a triangle
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Nov 18, 2020 at 0:35 | comment | added | RavenclawPrefect | A parallel discussion of this question several years ago on /r/mathriddles: reddit.com/r/mathriddles/comments/37xj7i/… | |
| Apr 13, 2020 at 6:32 | history | edited | Martin Sleziak |
added a top-level tag; https://meta.mathoverflow.net/questions/1457/why-are-mo-tags-formatted-as-they-are
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| Apr 13, 2020 at 0:28 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
added 8 characters in body
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| Apr 13, 2020 at 0:06 | history | edited | Wlodek Kuperberg | CC BY-SA 4.0 |
added 20 characters in body
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| Apr 12, 2020 at 12:58 | answer | added | Wlod AA | timeline score: 3 | |
| Oct 21, 2019 at 7:17 | comment | added | achille hui | Joe's answer $2(\sqrt{2}-1)$ is indeed the optimal one. In fact, for any triangle with area $1$, one can always find a rectangle of area $1$ so that their intersection has area $2(\sqrt{2}-1)$. For a proof, see my answer to a similar question on math.SE. | |
| Jan 30, 2018 at 1:14 | comment | added | Wlodek Kuperberg | Very interesting indeed. Thank you. | |
| Oct 8, 2017 at 18:48 | comment | added | yarchik | I have asked a question about the numerical optimization of your problem on mathematica.stackexchange.com/questions/156677/… You might find it interesting | |
| Sep 28, 2017 at 14:36 | history | edited | Wlodek Kuperberg | CC BY-SA 3.0 |
Question adjusted due to answer by Joseph O'Rourke.
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| Sep 28, 2017 at 0:32 | answer | added | Joseph O'Rourke | timeline score: 10 | |
| Sep 27, 2017 at 23:52 | history | edited | Wlodek Kuperberg | CC BY-SA 3.0 |
deleted 3 characters in body
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| Sep 27, 2017 at 23:46 | history | asked | Wlodek Kuperberg | CC BY-SA 3.0 |