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Sep 25, 2017 at 12:49 answer added Wojowu timeline score: 6
Sep 25, 2017 at 12:38 comment added Lwins It seems like that this question is strongly related to diophantine approximation. By Hurwitz's theorem $(x,y)=(0,2)$ is OK, as Mateusz Kwaśnicki said. Furthermore I think that $(x,y)>(0,2)$ may failed for the same reason.
Sep 25, 2017 at 12:16 comment added Mateusz Kwaśnicki On the other hand, $x = 0$ and $y = 2$ does the job. @StefanKohl: Do you have any conjectured answer?
Sep 25, 2017 at 12:09 comment added Wojowu Not for any $x,y$ both greater than $1$, by measure reasons.
Sep 25, 2017 at 12:04 history asked Stefan Kohl CC BY-SA 3.0