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Sep 22, 2017 at 5:18 comment added naf $S_1$ and $S_2$ are certainly not projectively equivalent since the linear systerms on $A$ are not the same. Whether or not there exists an $f$ is an interesting question; I had thought about this some years ago but was not able to reach any conclusion.
Sep 21, 2017 at 13:47 history asked Bernie CC BY-SA 3.0