Taylor said that he's never heard of anyone proposing a similar direct description of G$G$ and that to understand G$G$ one studies the representations of G$G$.
I remember Mazur telling me this when I was a grad student. HeHe made this point in the following way. YouYou shouldn't really think of Gal(Qbar/Q)$\mathrm{Gal}(\bar{\mathbb{Q}}/\mathbb{Q})$ as a group which has elements, but as a "group up to conjugacy" -- thus, the aspects of Galois groups that really make sense to think about are the conjugacy-invariant things: conjugacyconjugacy classes (like Frobenii) and representations.
To unpack this a bit more: aa Galois group is a fundamental group. ButBut to talk about a fundamental group (as opposed to a groupoid) you need to choose a basepoint. ToTo talk about an absolute Galois group you also need to choose a basepoint, which is to say an algebraic closure Qbar/Q$\bar{\mathbb{Q}}/\mathbb{Q}$. (So just as one should talk about pi_1(X,*)$\pi_1(X,*)$ rather than pi_1(X)$\pi_1(X)$, one should talk about Gal(Qbar/Q)$\mathrm{Gal}(\bar{\mathbb{Q}}/\mathbb{Q})$ rather than Gal(Q)$\mathrm{Gal}(\mathbb{Q})$.) ButBut a basepoint you can just draw with a pencil. AA Galois closure of Q$\mathbb{Q}$ is not so easy.