Timeline for Does the orthogonal group act irreducibly on totally symmetric tensors?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 12, 2017 at 14:41 | vote | accept | Dustin G. Mixon | ||
| Sep 12, 2017 at 13:05 | review | Close votes | |||
| Sep 12, 2017 at 13:35 | |||||
| Sep 12, 2017 at 13:05 | answer | added | Friedrich Knop | timeline score: 12 | |
| Sep 12, 2017 at 12:41 | comment | added | Thomas Richard | Will Sawin's comment corresponds to the fact that the identity matrix is a fixed point of the action of $O(d)$ on the space of symmetric $d\times d$ matrices. | |
| Sep 12, 2017 at 12:33 | comment | added | Will Sawin | This is false. If $k=2$, $\sum_{i=1}^d e_i \otimes e_i$ is an invariant vector. | |
| Sep 12, 2017 at 12:23 | history | asked | Dustin G. Mixon | CC BY-SA 3.0 |