Timeline for On odd perfect numbers and a GCD
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 15, 2020 at 6:41 | answer | added | Jose Arnaldo Bebita | timeline score: 1 | |
| S Feb 9, 2020 at 16:11 | history | suggested | Jose Arnaldo Bebita | CC BY-SA 4.0 |
added cross-post hyperlink to MSE
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| Feb 9, 2020 at 15:06 | comment | added | András Bátkai | See also math.stackexchange.com/questions/3131818 | |
| Feb 9, 2020 at 14:23 | review | Suggested edits | |||
| S Feb 9, 2020 at 16:11 | |||||
| Mar 2, 2019 at 13:24 | answer | added | Jose Arnaldo Bebita | timeline score: 1 | |
| Sep 13, 2017 at 14:29 | comment | added | Jose Arnaldo Bebita Dris | If the downvoter could kindly explain his/her vote, I would consider it as constructive feedback. As it is, I am totally clueless. | |
| S Sep 12, 2017 at 2:13 | history | suggested | Jose Arnaldo Bebita | CC BY-SA 3.0 |
added context
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| Sep 12, 2017 at 1:42 | review | Suggested edits | |||
| S Sep 12, 2017 at 2:13 | |||||
| Sep 12, 2017 at 0:51 | comment | added | Jose Arnaldo Bebita | $G = i(q)$ if $i(q) \mid n$. Usually, this is the case when $i(q)$ is prime (since $i(q) \mid n^2$ must hold). Alas, the statement $i(q)$ is prime has been disproved in Chen and Chen (2012). | |
| Sep 11, 2017 at 17:40 | history | asked | Jose Arnaldo Bebita Dris | CC BY-SA 3.0 |