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Sep 28, 2017 at 16:02 vote accept C.F.G
S Sep 18, 2017 at 6:40 history suggested C.F.G CC BY-SA 3.0
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S Sep 18, 2017 at 6:40
Sep 10, 2017 at 21:55 history edited L.F. Cavenaghi CC BY-SA 3.0
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Sep 10, 2017 at 19:00 comment added Deane Yang I think the point of the question is asking what is known assuming only Hermitian and not necessarily Kahler.
Sep 10, 2017 at 18:05 history edited L.F. Cavenaghi CC BY-SA 3.0
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Sep 10, 2017 at 17:56 comment added L.F. Cavenaghi @SebastianGoette, please, consider to see my edit, in fact I was mistaken.
Sep 10, 2017 at 17:56 history edited L.F. Cavenaghi CC BY-SA 3.0
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Sep 10, 2017 at 17:47 comment added L.F. Cavenaghi @SebastianGoette, perhaps I am mixing things, but at Joyce's book (Compact manifolds with special holonomy) he proposes a general statement for Calabi-Yau theorem similar to my last comment. From such statement we can yield similar results as: if $c_1(M) = 0$ then there exists a K\"ahler-Ricci flat metric on $M$.
Sep 10, 2017 at 17:38 comment added L.F. Cavenaghi @SebastianGoette, If I am not mistaken, provided $c_1(M) > 0$, $M$ is compact and Kaehler, we have a $(1,1)$-form $\rho'$ at the same cohomology class of the Ricci form $\rho$ of the initial K\"ahler metric on $M$. By Calabi-Yau theorem we can find a K\"ahler metric such the Ricci form is $\rho'$.
Sep 10, 2017 at 16:54 comment added Sebastian Goette Which Calabi-Yau theorem are you referring to? If I remember correctly, there are additional conditions needed if $c_1(M)>0$, see wikipedia.
Sep 10, 2017 at 2:38 history edited L.F. Cavenaghi CC BY-SA 3.0
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Sep 10, 2017 at 2:37 comment added L.F. Cavenaghi If I am not mistaken just in the Kahler case, sorry for not pointing it out.
Sep 10, 2017 at 2:19 comment added Fan Zheng So does the condition "Ricci is nonnegative everywhere and positive at a point" imply the first Chern class is positive?
Sep 9, 2017 at 23:55 history answered L.F. Cavenaghi CC BY-SA 3.0