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when toggle format what by license comment
Sep 5, 2017 at 17:34 vote accept CommunityBot
Sep 5, 2017 at 15:35 history edited user113782 CC BY-SA 3.0
edited typos in (N2) and (N3)
Sep 5, 2017 at 15:16 history edited Martin Sleziak
added (orlicz-spaces) tag
Sep 5, 2017 at 13:11 answer added Gerald Edgar timeline score: 0
Sep 5, 2017 at 13:09 comment added user113782 Ok, I can see how this will work for positive and disjoint elements. If $\lvert x\rvert \wedge \lvert y\rvert = 0$ then $\lvert x\rvert \vee \lvert y\rvert = \lvert x\rvert + \lvert y\rvert$ and the result follows from (N3) because $\rho(\alpha x)$ is known to be non-decreasing function of $\alpha$ on $[0,\infty)$ for any fixed $x$.
Sep 5, 2017 at 12:55 comment added user113782 @GeraldEdgar For positive $x$ and $y$ it is certainly true. But what then?
Sep 5, 2017 at 12:24 comment added Gerald Edgar Perhaps you need to prove $$\alpha x+\beta y\le x+y \text{ for all } \alpha,\beta\ge0,\alpha+\beta=1,$$ maybe just for positive $x,y$. Is that true in a vector lattice?
Sep 5, 2017 at 11:57 history edited Martin Sleziak
added top-level tag; http://meta.mathoverflow.net/questions/1457/why-are-mo-tags-formatted-as-they-are
Sep 5, 2017 at 11:54 history asked user113782 CC BY-SA 3.0