Timeline for Action on cohomology of the power map of $K(Z,n)$
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Sep 5, 2017 at 2:21 | comment | added | Nicholas Kuhn | I'm most familiar with the mod p cohomology of $K(\mathbb Z/p,n)$'s, where the image of $e^*$ does generate the cohomology ring. But I am dubious that this holds integrally. | |
| Sep 5, 2017 at 2:07 | comment | added | Vitali Kapovitch | I was hoping my question can be answered without explicitly computing $H^*(K(\mathbb Z), n),\mathbb Z)$ which I know is hard to compute. Perhaps by induction on $n$ by analyzing the spectral sequence of $K(\mathbb Z,n)\to\star\to K(\mathbb Z,n+1)$. | |
| Sep 5, 2017 at 1:31 | history | answered | Nicholas Kuhn | CC BY-SA 3.0 |