Skip to main content

Timeline for Computation of a minimal polynomial

Current License: CC BY-SA 3.0

9 events
when toggle format what by license comment
Sep 3, 2017 at 19:59 comment added J. M. isn't a mathematician Mathematica would also allow you to do things like MinimalPolynomial[Root[#^5 - # + 1 &, 1] - Root[#^5 - # + 1 &, 5], x], to use @Anton's example.
Sep 3, 2017 at 17:49 comment added Igor Rivin @Anton The problem is that you cannot algebraically distinguish one from another. So, some differences $\alpha - \beta$ of roots of your favorite polynomial are equal to zero, so their minimal polynomial is $x.$ The characteristic polynomial of the rational number $\alpha - \beta$ will be thus divisible by powers of $x.$
Sep 3, 2017 at 16:59 comment added Anton Thanks, I appreciate that! Though I don't quite understand what do you mean by "characteristic polynomial will be reducible". Say, I know that if a and b are two distinct roots of x^5-x+1, then the minimal polynomial of a-b is x^20-10*x^16-...+5000x^2+2869, a.k.a. the characteristic polynomial of a companion matrix of a-b, is irreducible. What's the problem here?
Sep 3, 2017 at 16:43 history edited Igor Rivin CC BY-SA 3.0
added example
Sep 3, 2017 at 16:40 comment added Igor Rivin @Anton In that case, the characteristic polynomial will be reducible (because the roots of the characteristic polynomials will also include things like $2\alpha.$). I will add mathematica code.
Sep 3, 2017 at 16:34 vote accept Anton
Sep 3, 2017 at 16:28 history edited Igor Rivin CC BY-SA 3.0
fixed paren
Sep 3, 2017 at 16:26 comment added Anton Thank you, Igor! I think this is precisely what I was looking for. Can you give an example of how this works w.r.t. two distinct roots of x^5-x+1? I don't quite understand how this works when two distinct algebraic numbers have the same companion matrix.
Sep 3, 2017 at 16:13 history answered Igor Rivin CC BY-SA 3.0