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Sep 3, 2017 at 17:35 vote accept Ivica Smolić
Sep 2, 2017 at 19:41 comment added Ivica Smolić @abx: Yes, true... I was just hoping to find some additional assumption on the manifold that would force $H^3$ and $H^3_c$ to be isomorphic, or at least simultaneously trivial.
Sep 2, 2017 at 19:36 comment added abx @Ivica: yes, the two spaces are canonically isomorphic -- this is the duality theorem (Hatcher 3.35) that you quote in your post.
Sep 2, 2017 at 19:30 comment added Ivica Smolić @ David Speyer: Thanks for the very simple counterexample! But, if $H_1(\mathbb{R}^4 - \{0\}) \cong 0$, does this imply that at least $H^3_c(\mathbb{R}^4 - \{0\}) \cong 0$?
Sep 2, 2017 at 19:18 history answered David E Speyer CC BY-SA 3.0