Timeline for When a Killing vector field on Riemannian manifold $(M,g)$ is gradient?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 2, 2017 at 16:08 | vote | accept | C.F.G | ||
| Sep 2, 2017 at 15:17 | comment | added | Robert Bryant | @C.F.G: I really don't understand you. My examples are correct examples of what they claim: The first is a gradient vector field that is also a unit Killing field, the second is a unit Killing Field that is not a gradient vector field (even locally). In your comment/question, you didn't say what you meant by 'it', so I couldn't answer your question. Are you asking whether a gradient Killing field is necessarily a unit vector field? (Answer: no.) Are you asking whether a Killing field is necessarily a unit vector field? (Answer: no.) Please ask your question in a complete self-contained way. | |
| Sep 2, 2017 at 13:23 | comment | added | C.F.G | for Killing vector field! if this vector field is not unit then your examples are correct? | |
| Sep 2, 2017 at 9:28 | comment | added | Robert Bryant | @C.F.G: I'm sorry, but I don't understand your question. Necessary for what? | |
| Sep 1, 2017 at 11:02 | history | answered | Robert Bryant | CC BY-SA 3.0 |