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Jun 13, 2010 at 17:24 vote accept Jesse Burke
Jun 13, 2010 at 4:09 comment added BCnrd So yes, it is the question you meant to ask. A finite collection of polynomials with indeterminate coefficients is parameterized by a big affine space, and at the generic point the coefficients are true indeterminates (whereas at the origin the polys are all zero, etc.). Working over a dense open in this affine space is precisely considering coefficients avoiding some nontrivial algebraic relations. There's a huge development in EGA IV3 showing how results at a generic fiber imply results over dense opens (thereby "justifying" the name "generic point").
Jun 13, 2010 at 2:43 comment added Jesse Burke I don't think that's the question I meant to ask. I used generic in a different sense: take polynomials with coefficients in a field and replace those coefficients with new variables. I think one of the problems that I'm having is that I don't see how generic in that sense relates to the notion of generic point of a scheme.
Jun 13, 2010 at 1:38 history answered Boyarsky CC BY-SA 2.5