Timeline for Isometric imbedding of ellipsoidal projective plane
Current License: CC BY-SA 3.0
8 events
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Sep 16, 2017 at 0:24 | history | edited | Anton Petrunin | CC BY-SA 3.0 |
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Aug 29, 2017 at 16:37 | comment | added | Anton Petrunin | @RobertBryant The map with $\alpha=1$ and $\beta=0$ is expanding, so moving the center away and rescaling we get a length preserving map. | |
Aug 29, 2017 at 16:31 | comment | added | Robert Bryant | You are very kind. Mainly, I just wanted to convince myself that the roots were real, which was not obvious to me. I suppose it's also worth mentioning that, for the analogous construction for general $n$, the solutions have $\alpha^2= 1/2$ and $\beta = (-1\pm\sqrt{n{+}2})/(n{+}1)$. | |
Aug 29, 2017 at 16:19 | history | edited | Anton Petrunin | CC BY-SA 3.0 |
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Aug 29, 2017 at 15:08 | history | edited | Robert Bryant | CC BY-SA 3.0 |
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Aug 29, 2017 at 12:37 | comment | added | Robert Bryant | I believe that $\alpha = 1/\sqrt2$ and either $\beta=-1$ or $\beta = \frac13$ will give the desired isometric embedding of $\mathbb{RP}^2$ into $S^5\subset\mathbb{R}^6$. It may be worth mentioning that this map is equivariant with respect to actions of $\mathrm{SO}(3)$ on $\mathbb{R}^3$ and $\mathbb{R}^6$. | |
Aug 28, 2017 at 23:07 | history | edited | Anton Petrunin | CC BY-SA 3.0 |
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Aug 28, 2017 at 21:11 | history | answered | Anton Petrunin | CC BY-SA 3.0 |