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Aug 26, 2017 at 10:31 history edited Mare CC BY-SA 3.0
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Aug 26, 2017 at 9:10 history edited Mare CC BY-SA 3.0
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Aug 26, 2017 at 9:05 comment added Mare @JasonStarr Im sorry. I forgot to add that my algebras are finite dimensional. So for me symmetric means that it is a Frobenius algebra with symmetric bilinear form. In this situation the algebras always have infinite global dimension expect when they are semisimple.
Aug 26, 2017 at 9:04 history edited Mare CC BY-SA 3.0
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Aug 26, 2017 at 9:03 comment added Jason Starr For you, what is a symmetric algebra? For a polynomial ring $A=k[x_1,\dots,x_n]$, which many of us consider to be a "symmetric algebra" on $kx_1\oplus \dots \oplus kx_n$, the module $M=A/\langle x_1,\dots,x_n \rangle$ is indecomposable, it is not projective, and $\psi_M$ equals $n$. This continues to be true if you localize $A$ at the maximal ideal $\langle x_1,\dots,x_n \rangle$.
Aug 26, 2017 at 9:00 history edited Mare CC BY-SA 3.0
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Aug 26, 2017 at 8:55 history asked Mare CC BY-SA 3.0