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Jun 12, 2010 at 20:28 comment added T.. I think you are referring to Shelah+Woodin, "Large cardinals imply that every reasonably definable set of reals is Lebesgue measurable", Israel J Math 70 (1990) 381-394 showing that $AD_{L(R)}$ follows from supercompact cardinals. How does this relate to provable measurability rather than measurability per se?
Jun 12, 2010 at 19:20 comment added François G. Dorais Such assumptions, like L(R) satisfies AD, have very high consistency strength.
Jun 12, 2010 at 19:02 comment added T.. @FGD: +1 ! But are there any results on what constructions do stay inside the provably-measurable world?
Jun 12, 2010 at 18:42 comment added François G. Dorais It's not true that any construction in ZF + DC is guaranteed to stay within the realm of provably Lebesgue measurable sets. A simple example is a nonmeasurable set in L; the reason why it is measurable in Solovay's model is that every such set is countable in that model.
Jun 12, 2010 at 18:27 history answered T.. CC BY-SA 2.5