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Aug 26, 2017 at 15:39 comment added user43198 @R.vanDobbendeBruyn For me, simple means that $\mathrm{End}(\mathcal{F})=k$.
Aug 26, 2017 at 12:52 comment added R. van Dobben de Bruyn Yeah. Not sure if it's standard terminology. And depending on which definition of simple you use, it may or may not be automatic (does simple mean that $\operatorname{End}(\mathscr F)$ is a division algebra, or that it equals $k$?).
Aug 26, 2017 at 6:36 comment added user43198 @R.vanDobbendeBruyn Thanks. By "(geometrically) simple", you mean simple as well as its pull-back to algebraic closure is simple?
Aug 26, 2017 at 2:33 comment added R. van Dobben de Bruyn Any geometrically stable sheaf $\mathscr F$ on a smooth projective $k$-variety $X$ is (geometrically) simple. Indeed, as you note, by flat base change it suffices to prove the result for $k = \bar k$. Then stability implies that a nonzero endomorphism $\phi \colon \mathscr F \to \mathscr F$ has to be surjective, since otherwise either $\operatorname{im} \phi$ or $\ker \phi$ has to be a proper subsheaf of larger slope. But a surjective endomorphism of a coherent sheaf is an isomorphism (see e.g. here).
Aug 25, 2017 at 11:08 history edited user43198 CC BY-SA 3.0
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Aug 25, 2017 at 10:58 history edited Ben McKay CC BY-SA 3.0
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Aug 25, 2017 at 10:47 history edited user43198 CC BY-SA 3.0
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Aug 25, 2017 at 8:16 history asked user43198 CC BY-SA 3.0