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Oct 13, 2018 at 1:46 comment added mme I'm not sure which version of Pin bordism the article "Pin Cobordism and Related Topics" refers to, but it states that $\overline\Omega_{n+1}^{\text{Spin}}(B\Bbb Z/2) = \Omega_n^{\text{Pin}}$. This would give you the desired result, by precisely the AHSS argument you suggest, and the spin bordism result you mention (which is I think more well-known).
Oct 13, 2018 at 1:38 comment added Arun Debray @MikeMiller I don't know. It should be about as hard as the analogous fact for spin bordism.
Oct 12, 2018 at 22:45 comment added mme Is it obvious there isn't any p-torsion in Pin^- bordism of a point itself (the $q_1=0$ line of your spectral sequence)? The OP indicates this is true to degree 4, at least.
Oct 12, 2018 at 21:29 history edited Arun Debray CC BY-SA 4.0
correctly spelling Tillmann
Oct 16, 2017 at 16:12 history edited Arun Debray CC BY-SA 3.0
removed assumption that this method fails to detect odd torsion, added explanation
Aug 22, 2017 at 17:14 history answered Arun Debray CC BY-SA 3.0